(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

6.83 mL of a solution of NaOH is standardized against 3.06 g of potassium hydrogen phthlate

(KHC8O4H4). Calculate the concentration of the base.

2. Relevant equations

c=n/v

M of KHP = 198.201

3. The attempt at a solution

Here is what I did.

Calculated moles of pottassium hydrogen phthalate

3.06/198.201 = 0.0154 mol.

Used the volume of naoh to calculate concentration.

c=n/v . c= 0.0154/ 0.00683

c= 2.25 mol/L

The answer is 2.15. What have i done wrong?

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# Homework Help: Acid-base equilibrium question titration

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