6.83 mL of a solution of NaOH is standardized against 3.06 g of potassium hydrogen phthlate
(KHC8O4H4). Calculate the concentration of the base.
M of KHP = 198.201
The Attempt at a Solution
Here is what I did.
Calculated moles of pottassium hydrogen phthalate
3.06/198.201 = 0.0154 mol.
Used the volume of naoh to calculate concentration.
c=n/v . c= 0.0154/ 0.00683
c= 2.25 mol/L
The answer is 2.15. What have i done wrong?