Acid base titration problem. Need Help

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SUMMARY

The forum discussion focuses on calculating the moles of H3O+ required to adjust the pH of a solution from 7.17 to 5.85. The correct calculation yields 1.34E-6 moles of H3O+. The relationship between pH and molar concentration is emphasized, with pH 7.17 corresponding to a concentration of 6.76 x 10-8 M. The method involves determining the molar concentration for the target pH and calculating the difference to find the required moles of H3O+.

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How many moles of H3O+ must be added to one liter of a solution to adjust the pH from 7.17 to 5.85?

Correct answer 1.34E-6 (1.34 * 10-6)

The correct answer is given, however I would like to know how to do this problem.
 
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See definition of pH - http://www.chembuddy.com/?left=pH-calculation&right=pH-definition

The pH is related to the molar concentration.

pH = 7.17 yields a molar concentration of 10-7.17 = 6.76 x 10-8 M, or moles/liter

Now try to find the number of moles in one liter for pH = 5.85.

Take the difference which gives the number of moles of H+ or H3O+ one needs to add to one liter.
 

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