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Adding Back Spectator Ions When Balancing Equations

  1. Oct 2, 2006 #1
    Here is what I have:
    [tex]BrO_{3}^{-} + NH_{3}OH^{+} + H_{2}O --> Br^{-} + NO_{3}^{-} + 2H_{3}O^{+}[/tex]

    I'm adding back spectator ions, K+ and Cl-.
    [tex]KBrO_{3} + NH_{3}OHCl + H_{2}O --> KBr + KNO_{3} + 2H_{3}O^{+} + HCl[/tex]

    As you can see I have 1 K and 1 Cl on the left, but 2 K and 1 Cl on the right. And because I was required to add HCl, another hydrogen has been added (unbalancing the equation).
    How would I go about solving this problem? Would I add more hydrogen to the left side? And what would I do about the unbalanced # of K's?
     
    Last edited: Oct 2, 2006
  2. jcsd
  3. Oct 3, 2006 #2

    Borek

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    Staff: Mentor

    First of all - original reaction is not balanced. Read this balancing lecture to learn how to check if the reaction is balanced.

    Hint: check charges.
     
  4. Oct 4, 2006 #3
    The charges are balanced. :S I just figured out the answer though. Thanks for your help anyway. :)
     
  5. Oct 4, 2006 #4

    Borek

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    Staff: Mentor

    Oops, sorry, missed 2 before H3O+ :blushing:
     
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