Adding scientific notation question =)

Click For Summary
The discussion revolves around the addition of three values in scientific notation: (9.8x10^3s), (9.9x10^4s), and (0.017x10^6s). The user attempted to submit answers of 125800 and 1.26x10^5, but both were marked incorrect, likely due to issues with significant figures. The correct approach involves aligning the numbers to a common exponent and ensuring the final answer adheres to the proper significant figures. The consensus is that the user needs to adjust their answer to reflect the correct number of significant digits. Understanding significant figures is crucial for correctly solving problems in scientific notation.
dolpho
Messages
66
Reaction score
0

Homework Statement


Add (9.8x10^3s)+(9.9x10^4s)+(0.017x10^6s)

Homework Equations


None

The Attempt at a Solution


I have entered 125800, as well as 1.26x10^5 but the website marked both of those wrong. I've done this problem every way you could do it I think and it comes out to the same answer but the program won't accept it.
 
Physics news on Phys.org
I presume this has to do with significant digits a.k.a significant figures.

(9.8x103s) + (9.9x104s) + (0.017x106s) = (0.98x104s) + (9.9x104s) + (1.7x104s)
 
SammyS said:
I presume this has to do with significant digits a.k.a significant figures.

(9.8x103s) + (9.9x104s) + (0.017x106s) = (0.98x104s) + (9.9x104s) + (1.7x104s)

So I worked out your problem also and it gave me 125800 and it just says add, but I'm guessing it doesn't want the answer but what you gave instead. Ugh I hate mastering physics... :(
 
dolpho said:
Add (9.8x10^3s)+(9.9x10^4s)+(0.017x10^6s)

I have entered 125800, as well as 1.26x10^5

You were already pointed to significant figures. Both numbers you have tried have too many.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 27 ·
Replies
27
Views
13K
Replies
5
Views
2K
Replies
5
Views
11K
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 35 ·
2
Replies
35
Views
11K
Replies
17
Views
5K