- #1

- 1,462

- 44

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- #1

- 1,462

- 44

- #2

- 18,517

- 21,350

- #3

Science Advisor

- 8,140

- 571

- #4

- 18,517

- 21,350

##a \cdot a \cdot a## isn't defined without associativity. And what if ##a \cdot b \neq b \cdot a## with ##b=a^2\,##? Of course this doesn't happen in a group, because of associativity. But it cannot be ruled out for an algebra.

- #5

- 1,462

- 44

Okay. Well given that I understand that the associative law will have to be used, how do I in general go about doing an induction when there are two variables m and n instead of just n?allowthis abbreviation in the first place.

- #6

- 18,517

- 21,350

Share:

- Replies
- 7

- Views
- 914

- Replies
- 4

- Views
- 920

- Replies
- 42

- Views
- 3K

- Replies
- 6

- Views
- 1K

- Replies
- 3

- Views
- 630

- Replies
- 1

- Views
- 649

- Replies
- 7

- Views
- 867

- Replies
- 2

- Views
- 704

- Replies
- 52

- Views
- 5K

- Replies
- 3

- Views
- 867