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Aharonov-Bohm Effect: Calculate fringe shift

  1. Oct 16, 2014 #1
    I am trying to figure out when electrons are subject to an Aharonov-Bohm apparatus (the pick up a phase of +/- e(magnetic_flux)/(h_bar), how the interference fringes are shifted.

    I know de Broglie wavelength is given by lambda = h/p and that the fringe spacing without the vector potential is given by y=D*lambda/d where D is the distance to the screen and d is the slit spacing.

    Thanks.
     
  2. jcsd
  3. Oct 17, 2014 #2

    DrClaude

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    Staff: Mentor

    The Aharonov-Bohm effect doesn't change the spacing of the fringes, only shifts them. To calculate the exact shift, precise knowledge of the position of the electron source, slits, and screen, along with the vector potential, is needed.
     
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