An extremely basic question on MCNP

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The discussion revolves around calculating the dose rate from an MCNP simulation involving a Co-60 source within a spherical air volume. The user obtained a tally result of 1.4657E-15 mSv/h/particle and sought guidance on how to convert this to a dose rate for a source activity of 1E+6 Bq. A method was shared that involves calculating the number of emitted photons and using conversion factors from ICRP 74 to derive the dose equivalent rate. The final calculation provided a dose rate of 3.44E-7 Sv/h. The user expressed gratitude for the clarification received.
Takvorian
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How to calculate the gamma dose rate from MCNP results ?
Hi there,

I have a very simple question about MCNP (6.2 to be precise) ... maybe someone here might enlighten me ...

Based on the (more than simple) MCNP input file below, which describes a sphere with R=200cm, filled with air and a point source in the center. There's a single ring tally on the X axis in a distance of 100 cm from the source, which should give the results in mSv/h/particle. The source is Co-60 with its 3 gamma photons defined.

When I run that file, the tally F15 gives me a value of 1.4657E-15 mSv/h/particle (error is 0.0008).

Question: How do I calculate the correct dose rate for a source with i.e. 1E+6 Bq from that tally result ?

Greetings and may that not too boring a question ... but that topic seems to be a bit neglected in the manuals and lectures ... :(

Takvorian

[CODE title="MCNP input"]MCNPX Visual Editor Version X_25
c Created on: Wednesday, February 23, 2022 at 19:58
1 304 -0.001205 -1 imp:p=1
2 0 1 imp:p=0

c Welt
1 so 200 $Welt

mode p
m304 6000 -0.000124 $Air (Dry, Near Sea Level) Density: -0.001205
7014 -0.7525 7015 -0.0027668 8016 -0.23123
8017 -8.7866e-005 18036 -4.2793e-005 18038 -8.0671e-006
18040 -0.012776
sdef pos=0 0 0 ERG=D1
c
c source energies (Co-60)
si1 L 0.6938 1.1732 1.3325
sp1 D 1.6312e-4 1 1
c
f15x:p 100 1 -0.125
df15 IU 2 ic 10
stop F15 0.0005 [/CODE]
 
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Hi,
for my part to calculate dose equivalent rate, I use a function response (DE/DF).
The “de” card contains discrete energies and the “df” card provides the values of the conversion
factors from ICRP 74.
For example for photons in terms of H*(10) :
DE15 .01 .015 .02 .03 .04 .05 .06 .08 .1 .15 .2 .3 .4 .5 .6 &
.8 1 1.5 2 3 4 5 6 8 10
DF15 0.061 .83 1.05 .81 .64 .55 .51 .53 .61 .89 1.2 1.8 2.38 2.93 3.44 &
4.38 5.2 6.9 8.6 11.1 13.4 15.5 17.6 21.6 25.6

Your results are in pSv for one particle.
So for A=1E6 Bq you must calculate the number of photons :
N=1E6*( 1.6312e-4 + 1+ 1)=2E6 gamma/s
MCNP gives F5=4.7807E-05 (the unit is pSv per photon)
So H*(10)=4.7807E-05*1e-12*2E6*3600= 3.44E-7 Sv/h
I insert input and output files
This is well described in this book :
https://www.researchgate.net/publication/355444601_Radiation_problems_from_analytical_to_monte-carlo_solutions
 

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Likes Astronuc, Takvorian and berkeman
Thanks - that resolved my question.
 
What type of energy is actually stored inside an atom? When an atom is split—such as in a nuclear explosion—it releases enormous energy, much of it in the form of gamma-ray electromagnetic radiation. Given this, is it correct to say that the energy stored in the atom is fundamentally electromagnetic (EM) energy? If not, how should we properly understand the nature of the energy that binds the nucleus and is released during fission?

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