An small question about RSA algorithm

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Choosing e=1 or e=2 in the RSA algorithm is not viable because e must be coprime to φ(n), which is even when p and q are distinct primes. If e=1, the ciphertext would equal the plaintext, rendering the encryption ineffective. Additionally, e=2 is not permissible since it would not satisfy the coprime condition with φ(n). The requirement for e ensures the existence of a corresponding d that makes the encryption and decryption process functional. Therefore, selecting e values like 1 or 2 contradicts the fundamental purpose of RSA encryption.
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on the RSA algorithm

http://en.wikipedia.org/wiki/RSA

why simply we can not choose e=1 or e=2 ? it would simplify the calculations a lot.
 
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Does'nt that go against the purpose of the RSA?

edit: shady comma
 
If e = 1, then the ciphertext is the same as the plaintext, making the algorithm useless.

It's required that e is coprime to φ(n) = (p - 1)(q - 1), so that there exists d such that ed = 1 mod φ(n). However, if p and q are distinct primes, then one of them is odd, so φ(n) is even. Thus e can't be 2.
 
thanks a lot adriank , nice forum
 
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