Analyzing the Safety of a New Amusement Park Ride Prototype

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SUMMARY

The discussion focuses on analyzing the safety of a new Tilt-a-Whirl prototype, specifically evaluating whether it adheres to the guideline of a maximum of 3.5 g's of acceleration. The design features a distance of 20.0 m between pivots and tangential velocities of 6.0 m/s and 2.5 m/s for the two armatures. The distance from pivot C to the seat is 5 m. The participants are tasked with determining if the prototype meets safety standards based on these parameters.

PREREQUISITES
  • Understanding of centripetal acceleration and its calculation
  • Familiarity with the physics of rotational motion
  • Knowledge of g-force limits in amusement park rides
  • Basic principles of ride design and safety regulations
NEXT STEPS
  • Calculate centripetal acceleration using the formula a = v²/r
  • Research safety regulations for amusement park rides in various states
  • Explore the physics of non-circular motion in amusement rides
  • Examine case studies of similar ride prototypes and their safety evaluations
USEFUL FOR

Engineers, amusement park ride designers, safety inspectors, and physics students interested in ride safety and design principles.

tomboi03
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This is the Question:

Amusement parks are great fun and the venerable Tilt-a-Whirl is a perennial favorite. You are asked to examine a new prototype model with a little more whirl. General guidelines suggest a maximum of 3.5 g's on any ride (Note: amusement parks rides are not regulated at the federal level and so in many states there is really little or no oversight, caveat emptor). The general layout of the machine is sketched below and the design firm claims to have done its homework. The distance between pivots (A to B or B to C) is 20.0 m and the individual tangential velocities of the two armatures are 6.0 and 2.5 m/s respectively when the ride is operating a full power. The distance from the C pivot to the seat is set to 5m. Does this new design satisfy the guidelines?

So, basically... This is how far I got...

v2/r= rw2

So v=rw

\alpha= dw/dt
and a = v2/r

but since this is not a circle, I'm not sure how to go about this...?

Am i just thinking too hard? Is this a really easy problem that I'm viewing in a difficult way?
 
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Without an illustration it's a little hard to imagine what the A to B or B to C distances happen to be.
 


Here is the picture! :D

Sorry about that guys...
 

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