And for my next trick more ideal gases questions. the joy.

  • Thread starter Thread starter QueenFisher
  • Start date Start date
  • Tags Tags
    Gases Ideal gases
Click For Summary
SUMMARY

The discussion revolves around calculations involving an ideal gas contained in a cylinder with a volume of 2x10^-3 m³, a pressure of 1.50 MN/m², and a temperature of 300K. The number of moles was calculated using the ideal gas law, yielding approximately 1.203 moles. Subsequently, the number of molecules was determined to be approximately 7.224 x 10^23 using Avogadro's constant. The actual mass of the gas was calculated to be 38 grams based on a molar mass of 0.032 kg, clarifying the importance of unit conversion in calculations.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Familiarity with Avogadro's constant (6.023 x 10^23)
  • Knowledge of unit conversions (kg to grams)
  • Basic principles of molecular mass calculations
NEXT STEPS
  • Study the Ideal Gas Law and its applications in thermodynamics
  • Learn about unit conversion techniques in scientific calculations
  • Explore molecular mass and its significance in chemistry
  • Investigate the concept of significant figures in measurements and calculations
USEFUL FOR

Students studying chemistry, particularly those focusing on gas laws and molecular calculations, as well as educators looking for practical examples of ideal gas applications.

QueenFisher
as promised:

a cylinder of volume 2x10^-3 m^3 contains a gas at a pressure of 1.50MNm^-2 and at a temperature of 300K.

calculate number of moles. i think I'm ok with this bit:
n=(pV)/(RT)
=(1.5x10^6)x(2x10^-3) all divided by 8.31x300
gives 1.2033694...

calculate number of molecules.
number of molecules=number of moles x avocado's constant
=1.2033694 x 6.023x10^23
=7.224283x10^23

calculate the actual mass of the gas if the molar mass is 0.032kg
actual mass = number of moles x molecular mass
=32 x 1.2033694
=38.5078

now calculate the mass of one molecule of the gas.
erk! which equation do i use? i can't use the half-m-c-squared-bar ones cos i don't know speeds or anything!
help is appreciated.

i have yet another one! watch this space.
 
Physics news on Phys.org
Watch your significant figures. Really.
Also, use the units. The mass is not 38, but 38 kg.

So, you know the mass of the entire gas and you know how many molecules there are in the gas, but you cannot calculate the mass per molecule?
 
no the mass is 38 grams cos i converted the 0.032kg to grams when i put it in the equation.

but anyway i think that has solved my problem thanks!
 

Similar threads

Replies
4
Views
3K
Replies
8
Views
6K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
4
Views
3K
  • · Replies 13 ·
Replies
13
Views
4K