Angle of fuzzy dice when moving Just want to check

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SUMMARY

The discussion focuses on calculating the angle θ that a pair of fuzzy dice makes with the vertical while accelerating from a stop to 28 m/s in 6 seconds. The acceleration in the x-direction (Ax) is determined to be 4.7 m/s², while the acceleration in the y-direction (Ay) remains constant at 9.8 m/s². The angle is calculated using the formula tan θ = Y/X, resulting in θ = 25.6°. Participants emphasize the importance of precision in calculations and suggest maintaining extra decimal places until the final result is achieved.

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Homework Statement


a pair of fuzzy dice hang from your mirror. While you accelerate from a stop on a horizontal surface to 28 m/s in 6 s, what angle θ does the string make with the vertical?

Homework Equations



tan θ = Y/X

a = ΔV / Δt

The Attempt at a Solution



Just want a double check:

So we can use the accelerations to figure out the angle...

Ay = 9.8 m/s^2

Ax = (Δ V)/ Δ (t) = (28 m/s - 0)/(6 - 0) = 4.7 m/s^2

tan θ = 4.7 / 9.8 = 25.6°
 
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coneheadceo said:

Homework Statement


a pair of fuzzy dice hang from your mirror. While you accelerate from a stop on a horizontal surface to 28 m/s in 6 s, what angle θ does the string make with the vertical?

Homework Equations



tan θ = Y/X

a = ΔV / Δt

The Attempt at a Solution



Just want a double check:

So we can use the accelerations to figure out the angle...

Ay = 9.8 m/s^2

Ax = (Δ V)/ Δ (t) = (28 m/s - 0)/(6 - 0) = 4.7 m/s^2

tan θ = 4.7 / 9.8 = 25.6°

Your method is correct. Two things to keep in mind:
1. Don't be too free with the "=" symbol; the angle is not the same as the tan of the angle.
2. Keep a few extra decimal places in intermediate results and only round at the end for the final value.
 

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