Angular Displacement: 2π Radians

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Walking around a circular track results in a linear displacement of 0, as the starting and ending points are the same. However, the angular displacement is 2π radians, reflecting the full rotation around the circle. Angular displacement has both magnitude and direction but is not classified as a vector since it does not follow all vector laws, particularly the commutative property of addition. The direction of angular displacement can be determined using the right-hand rule. Therefore, while linear displacement is 0, angular displacement is definitively 2π radians.
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I walk around a circular track. My displacement is 0 because I'm back at my starting point.
How about my angular displacement? Is it 2 pi radians, or is it also 0? The definitions I've been reading online seem to indicate that 2 pi radians is the answer.
 
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tony873004 said:
I walk around a circular track. My displacement is 0 because I'm back at my starting point.
How about my angular displacement? Is it 2 pi radians, or is it also 0? The definitions I've been reading online seem to indicate that 2 pi radians is the answer.
Angular displacement has magnitude and direction, but it is not a vector because it does not obey all the laws of vectors, specifically, it does not obey the commutative property of addition. So the angular displacement when rotating full circle is 2pi radians , and it's direction is given by the right hand rule.
 
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