MHB Annual Average Percentage Increase

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To find the annual average percentage increase of a house that doubles in value over 20 years, the formula used is H = H0(1+r)^t. By setting H = 2H0 and t = 20, the equation simplifies to 2 = (1+r)^20. Solving for r involves raising both sides to the power of 1/20 and subtracting 1, leading to an approximate annual increase of 3.53%. The discussion emphasizes the simplicity of this calculation and suggests clearer topic titles for future queries.
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What is the simplest way of solving this?

The value of a house is doubled in 20 years. What is the annual average percentage increase, if it is assumed to be the same each year?
 
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I would let $H_0$ be the initial value of the house, and use the relation:

$\displaystyle H=H_0(1+r)^t$

We then let $H=2H_0$, $t=20$ and solve for $r$:

$\displaystyle 2H_0=H_0(1+r)^{20}$

$\displaystyle 2=(1+r)^{20}$

Now, raise each side to a power of $\dfrac{1}{20}$, then subtract 1 from each side, and you will have isolated $r$. Then multiply by 100, and use your calculator to get a decimal approximation if you want.

edit: Please let me suggest that your topic titles be more indicative of the nature of the question. I would use something like "Computing growth rate of investment" or something similar.
 
linapril said:
What is the simplest way of solving this?

The value of a house is doubled in 20 years. What is the annual average percentage increase, if it is assumed to be the same each year?
Very easy indeed...

$a= 2^{\frac{1}{20}} \sim 3.53 \text{%}$

Kind regards

$\chi$ $\sigma$
 
Could please explain how you got that answer?

chisigma said:
Very easy indeed...

$a= 2^{\frac{1}{20}} \sim 3.53 \text{%}$

Kind regards

$\chi$ $\sigma$
 
linapril said:
Could please explain how you got that answer?

MarkFl has already explained that in excellent way!... an alternative explanation is that the expression of the of value of the house after N years is...

$\displaystyle v= 2^{\frac{N}{20}}$ (1)

Now all what You have to do is setting in (1) N=1...

Kind regards

$\chi$ $\sigma$
 
I have been insisting to my statistics students that for probabilities, the rule is the number of significant figures is the number of digits past the leading zeros or leading nines. For example to give 4 significant figures for a probability: 0.000001234 and 0.99999991234 are the correct number of decimal places. That way the complementary probability can also be given to the same significant figures ( 0.999998766 and 0.00000008766 respectively). More generally if you have a value that...

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