Annual Average Percentage Increase

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Discussion Overview

The discussion revolves around calculating the annual average percentage increase in the value of a house that doubles over a period of 20 years, assuming a consistent growth rate each year. Participants explore different methods and formulas to arrive at this calculation.

Discussion Character

  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant suggests using the formula $\displaystyle H=H_0(1+r)^t$ to solve for the growth rate $r$, leading to the equation $\displaystyle 2=(1+r)^{20}$.
  • Another participant provides a direct calculation method, stating that the annual average percentage increase can be approximated as $a= 2^{\frac{1}{20}} \sim 3.53 \text{%}$.
  • A request for clarification on the calculation method is made, indicating that the result is considered straightforward by some participants.
  • Another participant offers an alternative expression for the value of the house after $N$ years, suggesting $\displaystyle v= 2^{\frac{N}{20}}$ and proposes substituting $N=1$ to find the annual increase.

Areas of Agreement / Disagreement

There is no clear consensus on a single method for calculating the annual average percentage increase, as participants present different approaches and calculations without resolving which is preferable.

Contextual Notes

Participants do not fully elaborate on the assumptions behind their calculations, such as the implications of compounding or the context of the growth rate in real-world scenarios.

linapril
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What is the simplest way of solving this?

The value of a house is doubled in 20 years. What is the annual average percentage increase, if it is assumed to be the same each year?
 
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I would let $H_0$ be the initial value of the house, and use the relation:

$\displaystyle H=H_0(1+r)^t$

We then let $H=2H_0$, $t=20$ and solve for $r$:

$\displaystyle 2H_0=H_0(1+r)^{20}$

$\displaystyle 2=(1+r)^{20}$

Now, raise each side to a power of $\dfrac{1}{20}$, then subtract 1 from each side, and you will have isolated $r$. Then multiply by 100, and use your calculator to get a decimal approximation if you want.

edit: Please let me suggest that your topic titles be more indicative of the nature of the question. I would use something like "Computing growth rate of investment" or something similar.
 
linapril said:
What is the simplest way of solving this?

The value of a house is doubled in 20 years. What is the annual average percentage increase, if it is assumed to be the same each year?
Very easy indeed...

$a= 2^{\frac{1}{20}} \sim 3.53 \text{%}$

Kind regards

$\chi$ $\sigma$
 
Could please explain how you got that answer?

chisigma said:
Very easy indeed...

$a= 2^{\frac{1}{20}} \sim 3.53 \text{%}$

Kind regards

$\chi$ $\sigma$
 
linapril said:
Could please explain how you got that answer?

MarkFl has already explained that in excellent way!... an alternative explanation is that the expression of the of value of the house after N years is...

$\displaystyle v= 2^{\frac{N}{20}}$ (1)

Now all what You have to do is setting in (1) N=1...

Kind regards

$\chi$ $\sigma$
 

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