I Antisymmetrizing a Factorized Polynomial Vanishes?

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The discussion centers on the claim from a paper that antisymmetrizing a term with k factors of (z_i - z_j) requires antisymmetrizing 2k variables, which is deemed impossible. The user questions this assertion by presenting an example of antisymmetrizing the product (z_1 - z_2)(z_3 - z_4) using the definition of the antisymmetrizer. They argue that this can be achieved by summing over all permutations of the indices and applying the appropriate signs. The confusion arises from the paper's assertion that such antisymmetrization leads to a vanishing result. Clarifying the conditions under which the antisymmetrizer vanishes is essential for resolving this discrepancy.
thatboi
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Hi all,
I am having trouble understanding the argument below equation (3.5) in https://arxiv.org/pdf/cond-mat/9605145.pdf where they claim that "Upon antisymmetrization, however, a term with ##k## factors of ##(z_{i}-z_{j})## would have to antisymmetrize ##2k## variables with a polynomial that is linear in each", which is impossible.

However, I thought that even for something like ##(z_{1}-z_{2})(z_{3}-z_{4})##, I can antisymmetrize this expression by just using the definition of the antisymmetrizer, i.e I sum over all permutations of the indices ##(1,2,3,4)## and include ##\pm## signs as appropriate depending on how many times an index has been shifted. So why does the paper claim that the antisymmetrizer vanishes?
Thanks.
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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