Area of Triangle: How to Calculate

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Homework Help Overview

The discussion revolves around the calculation of the area of a triangle given two sides and the included angle. The original poster expresses uncertainty about the question's requirements and seeks clarification.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the area formula and the sine function, questioning how to derive the area from known dimensions. Some participants suggest considering the triangle's height and base, while others emphasize that the triangle does not need to be a right triangle.

Discussion Status

The conversation is ongoing, with participants offering different perspectives on how to approach the problem. There is an emphasis on clarifying assumptions about the triangle's shape and dimensions, but no consensus has been reached yet.

Contextual Notes

The original poster's problem does not specify that the triangle is a right triangle, which raises questions about the assumptions being made in the discussion.

huntingrdr
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Homework Statement


Show that the area of a triangle with sides of lengths a and b with included angle theta is...

A = 1/2 a*b*sin(theta)

I am not sure what this question is really asking. Any help?


Homework Equations





The Attempt at a Solution

 
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i believe strongly that you can figure it out.
 
If the area of a triangle is 1/2 b*h, and sin theta = opp/hyp, then that means a=h and b=b. Correct? Now how do I prove that the area is 1/2 a*b*sin(theta). I drew a right triangle and labeled the sides a and b, and the angle theta.
 
It isn't necessarily a right triangle. Try making side "a" the base and dropping a height "h" down from the opposite corner.
 
GunnaSix said:
It isn't necessarily a right triangle. Try making side "a" the base and dropping a height "h" down from the opposite corner.
Furthermore, since the OP's problem states only that it is a triangle, he/she should not assume that it is a right triangle.
 

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