Hi all Hoping someone can figure out a problem. In the attached figure, A is the area of openings in a disc. Assume the segments 82, 84, 86, 88 are along a radius and are equal. Is it possible to prove that A4/A3 > A3/A2 > A2/A1? In thanks I'll share this, hope it's not old news. Some wit wrote it on a bathroom wall when I was an undergrad, I still think it's funny. [itex]\sqrt{(Doing)^{2} + (Being)^{2}}[/itex]= [itex]Doobee\,Doobee\,BingDing[/itex] J Fox
Never mind. Trying an idealized example of r=R, .75R, .5R, .25R it comes down to A4[itex]\propto[/itex] 1^{2}-.75^{2} A3[itex]\propto[/itex] .75^{2}-.5^{2} A2[itex]\propto[/itex] .5^{2}-.25^{2} A4/A3 < A3/A2 But it was cool to find the math font/language!