Arrow shot from a bow using spring energy

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whoopie88
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Homework Statement


An archer puts a 0.30 kg arrow to the bowstring. An average force of 192 N is exerted to draw the string back 1.3 m. Assume that air resistance is negligible.
(a) Assuming that all the energy goes into the arrow, with what speed does the arrow leave the bow?

(b) If the arrow is shot straight up, how high does it rise?

Homework Equations


All Energy/Work equations


The Attempt at a Solution


Handwritten physics working on lined paper: PE_e = KE_f, F = kx, and 192 = k(1.3), with 1/2 kx^2 = 1/2 mv^2 and 1/2 kx^2 = mgh; the work continues with (1/2)(147.7)(1.3)^2 = (1/2)(0.3)V_f^2, 192/1.3 = k, and 832.043 and 28.85 = V_f.


Thanks in advance for help!
 
Really? o.o I'm doing a Webassign, and it's telling me that my values are incorrect.
I put in 28.85 m/s for (a) and 42.4 m for (b).

Is there something I'm missing? o.o
 
whoopie88 said:
Really? o.o I'm doing a Webassign, and it's telling me that my values are incorrect.
I put in 28.85 m/s for (a) and 42.4 m for (b).

Is there something I'm missing? o.o

Given the values, it should be correct. Realistically speaking, 1.3 m is quite large for an archer to stretch the string.
 
whoopie88 said:
Really? o.o I'm doing a Webassign, and it's telling me that my values are incorrect.
I put in 28.85 m/s for (a) and 42.4 m for (b).

Is there something I'm missing? o.o

The "average" force is F, so the energy is F * 1.3

or

F = 192 = K* X /2 not K * X

So the velocity is 28.85 * sqrt(2) = 40.8m/sec