MHB [ASK] Are the Frequency and the Score Switched?

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The discussion revolves around a table that presents frequency and score data, leading to confusion about whether these values are switched. The original calculations for the average score yielded results that did not match any provided answer options. Upon reassessing the data with the assumption that frequency and score might be reversed, a new mean score of approximately 7.17 was calculated. This new mean indicated that 20 students scored above average, yet the answer options still did not align with the findings. The thread highlights the challenge in interpreting the data correctly and the importance of verifying assumptions in statistical calculations.
Monoxdifly
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Pay attention to the table below.
$$\begin{array}{|c|c|c|c|c|c|}\hline Frequency & 5 & 6 & 7 & 8 & 9 \\ \hline Score & 6 & 6 & 10 & 15 & 5\\ \hline \end{array}$$
The amount of students who get above average are...
A. 9 students
B. 17 students
C. 18 students
D. 26 students
I got the average as $$\frac{291}{35}$$, which is eight point something. So, I got 7 + 8 = 15 as the answer, but it was not in the option. I then assume that the frequency and score must be switched, but now I got $$\frac{291}{42}$$ which is six point something, so the answer should be 10 + 15 + 5 = 30 which was not in the options either. Where did I go wrong?
 
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Looking at the provided table, it appears the frequency and score are switched. Let's assume they are...

Using a weighted average, I get a mean score of:

$$\overline{x}=\frac{6\cdot5+6\cdot6+10\cdot7+15\cdot8+5\cdot9}{6+6+10+15+5}=\frac{301}{42}=\frac{43}{6}=7.1\overline{6}$$

It would appear 20 students scored higher than the mean. :D
 
That means, still no answer?
 
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