[ASK] find abc if a^2bc^3=5^3 and ab^2=5^6

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SUMMARY

The discussion focuses on solving the equations \(a^2bc^3=5^3\) and \(ab^2=5^6\) to find the value of \(abc\). A participant suggests that the second equation should be \(ac^2=5^6\) instead of \(ab^2=5^6\). By substituting and simplifying, it is concluded that \(abc=\frac{1}{125}\), which is derived from the relationship \(abc=\frac{5^3}{5^6}\).

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Monoxdifly
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If $$a^2bc^3=5^3$$ and $$ab^2=5^6$$, what does abc equal to? I'm stuck and always getting 0 = 0 or c = c.
 
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Monoxdifly said:
If $$a^2bc^3=5^3$$ and $$ab^2=5^6$$, what does abc equal to? I'm stuck and always getting 0 = 0 or c = c.

I have a feeling that you must have been told $\displaystyle \begin{align*} a\,c^2 = 5^6 \end{align*}$, not $\displaystyle \begin{align*} a\,b^2 \end{align*}$. Assuming that I am right...

$\displaystyle \begin{align*} a^2\,b\,c^3 &= 5^3 \\ a\,c^2\left( a\,b\,c \right) &= 5^3 \\ a\,b\,c &= \frac{5^3}{a\,c^2} \\ a\,b\,c &= \frac{5^3}{5^6} \\ a\,b\,c &= \frac{1}{5^3} \\ a\,b\,c &= \frac{1}{125} \end{align*}$
 

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