MHB [ASK] find abc if a^2bc^3=5^3 and ab^2=5^6

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To find the value of abc given the equations a^2bc^3=5^3 and ab^2=5^6, it is suggested that the second equation should actually be a*c^2=5^6. By manipulating the equations, it is derived that abc equals 1/125. This conclusion is reached by substituting and simplifying the expressions based on the corrected assumption. The final result indicates that abc is 1/125.
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If $$a^2bc^3=5^3$$ and $$ab^2=5^6$$, what does abc equal to? I'm stuck and always getting 0 = 0 or c = c.
 
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Monoxdifly said:
If $$a^2bc^3=5^3$$ and $$ab^2=5^6$$, what does abc equal to? I'm stuck and always getting 0 = 0 or c = c.

I have a feeling that you must have been told $\displaystyle \begin{align*} a\,c^2 = 5^6 \end{align*}$, not $\displaystyle \begin{align*} a\,b^2 \end{align*}$. Assuming that I am right...

$\displaystyle \begin{align*} a^2\,b\,c^3 &= 5^3 \\ a\,c^2\left( a\,b\,c \right) &= 5^3 \\ a\,b\,c &= \frac{5^3}{a\,c^2} \\ a\,b\,c &= \frac{5^3}{5^6} \\ a\,b\,c &= \frac{1}{5^3} \\ a\,b\,c &= \frac{1}{125} \end{align*}$
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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