Atomic Mass: Helium-4 Nucleus Contribution

  • Thread starter Thread starter AryaUnderfoot
  • Start date Start date
  • Tags Tags
    Mass Nucleus
Click For Summary
SUMMARY

The discussion focuses on calculating the fraction of mass contributed by the nucleus of a helium-4 atom, which has a total mass of 6.64648310224 g and two electrons each with a mass of 9.10939310228 g. The correct approach involves calculating the mass of the nucleus by subtracting the total mass of the electrons from the mass of the atom. The final fraction of the nucleus's mass is determined to be approximately 0.2673, contingent upon accurate values for the masses of the particles involved.

PREREQUISITES
  • Understanding of atomic mass and composition
  • Knowledge of significant figures in scientific measurements
  • Familiarity with basic arithmetic operations
  • Concept of mass-energy equivalence in physics
NEXT STEPS
  • Research the mass of subatomic particles, specifically protons and neutrons
  • Learn about significant figures and their importance in scientific calculations
  • Explore the concept of atomic mass units (amu) and their applications
  • Study the principles of nuclear physics related to atomic structure
USEFUL FOR

Students in physics or chemistry, educators teaching atomic structure, and anyone interested in understanding the composition of atoms and the significance of accurate measurements in scientific calculations.

AryaUnderfoot
Messages
17
Reaction score
0

Homework Statement


The mass of a helium-4 atom is 6.64648310224 g, and each of its two electrons has a mass of 9.10939310228 g. What fraction of this atom’s mass is contributed by its nucleus?

Homework Equations


fraction of mass = mass of nucleus/mass of atom

The Attempt at a Solution


I suppose I should calculate the mass of nucleus first. But I only have the mass of the electrons, no mass of neutron, also no density...
 
Physics news on Phys.org
Mass of nucleus = 6.64648310224
Mass of electrons = 9.10939310228 * 2
Mass of atom = 9.10939310228 * 2 + 6.64648310224 = 24.8652693068

Fraction of mass = mass of nucleus/mass of atom = 6.64648310224/24.8652693068 = 0.26729986392797124965341901615185

But the only problem is your data.
The masses of electron is not more than that of proton. And the mass of proton is too much.
I think you forgot to multiply the masses with power of 10s.
Well, this is the solution. Solve it in this way after you correct the data.
 
AryaUnderfoot said:
9.10939310228 g

That's incorrect on at least two accounts. First, digits after 9.1093 are wrong, second, the end should read not "28" but "e-28" - and this "e-" is what makes the most important difference.
 
Where is this question from? I find it hard to believe that these masses are known to anything like 12 significant figures.
 
epenguin said:
Where is this question from? I find it hard to believe that these masses are known to anything like 12 significant figures.

9.10938356(11)×10−31 kg, if you copy digits only you will get even 13 sigfigs :wink:
 
Aryamaan Thakur said:
Mass of nucleus = 6.64648310224
Mass of electrons = 9.10939310228 * 2
Mass of atom = 9.10939310228 * 2 + 6.64648310224 = 24.8652693068

Fraction of mass = mass of nucleus/mass of atom = 6.64648310224/24.8652693068 = 0.26729986392797124965341901615185

But the only problem is your data.
The masses of electron is not more than that of proton. And the mass of proton is too much.
I think you forgot to multiply the masses with power of 10s.
Well, this is the solution. Solve it in this way after you correct the data.
Ohh! I did a mistake
I thought 6.64648310224 is the mass of nucleus.

Correcting it!
Now,
Mass of nucleus = mass of atom - mass of electrons
And after you find it divide it with the mass of atom.

I hope you've verified the data.
 
  • Like
Likes   Reactions: AryaUnderfoot
10-27 kg is not the mass of the proton nor any nucleus.
 
Aryamaan Thakur said:
Ohh! I did a mistake
I thought 6.64648310224 is the mass of nucleus.

Correcting it!
Now,
Mass of nucleus = mass of atom - mass of electrons
And after you find it divide it with the mass of atom.

I hope you've verified the data.
Ah, my bad. I forgot the significant number behind the values..I got it now. Thanks!

And also sorry for late reply ^^
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 29 ·
Replies
29
Views
6K