Atomic Mass of Element X in XCl3 Stoichiometry Problem

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Discussion Overview

The discussion revolves around a stoichiometry problem involving the calculation of the atomic mass of an unknown element X in the compound XCl3, given specific mass data. Participants explore methods to approach the problem and clarify the relationships between the components of the compound.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents a calculation attempting to derive the atomic mass of X from the given mass of XCl3 and the mass of X, but expresses doubt about the validity of including the mass of X in the molar mass of XCl3.
  • Another participant calculates the mass of chlorine in the compound and suggests a method to find the ratio of formula units of X to Cl, indicating a potential approach to determine the moles of X.
  • A third participant acknowledges the correctness of an earlier answer but emphasizes the importance of not providing complete solutions to homework questions, suggesting a more guided approach instead.

Areas of Agreement / Disagreement

There is no clear consensus on the correct method to solve the problem, as participants offer different approaches and calculations without resolving the uncertainties or confirming a single solution.

Contextual Notes

Participants express uncertainty about the inclusion of certain mass values in calculations and the proper method for determining the atomic mass, indicating potential limitations in their assumptions or understanding of stoichiometry.

Who May Find This Useful

Students working on stoichiometry problems, particularly those involving the calculation of atomic masses in chemical compounds, may find this discussion relevant.

Benzoate
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Homework Statement



What is the atomic mass of element X if 6.08 g XCl3 contains 1.37 g of X

Homework Equations





The Attempt at a Solution



(6.08 g XCl^3)*(1 mol X/107.729 g *XCl3)*(1.37 g X/1 mol X)=.077 g of X

That can't be right , because 1.37 g of X can't be included in the molar mass of XCl3
 
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Long time since passed since doing stoichiometry exercises...

Total XCl3 was 6.08, since grams X was 1.37, amount of Cl mass was 4.71 grams.

How many formula units Cl ? 4.71/(35.5);
Ratio of X formula units to Cl formula units = 1/3

How many moles of X ? ((4.71)/(35.5))*(1/3)

Now you have calculated moles of X or formula units of X, and were given grams of X.
Finish the calculation.
 
Roco, your answer was correct, but we can't go about handing out complete solutions to homework questions.

Benzoate, to simplify symbolipt's method a wee bit...

Answer this question: If there's 4.71 gms of Cl3 and 1.37 gms of X (in a sample of XCl3), what is the formula mass of X?
 
Gokul43201 said:
Roco, your answer was correct, but we can't go about handing out complete solutions to homework questions.

Benzoate, to simplify symbolipt's method a wee bit...

Answer this question: If there's 4.71 gms of Cl3 and 1.37 gms of X (in a sample of XCl3), what is the formula mass of X?
sorry! will comply.
 

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