Average Percentages over 3 years

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SUMMARY

The discussion focuses on calculating the average percentage increase in population over three years for a town with populations of 1,000,000 in 2006, 1,200,000 in 2007, and 1,800,000 in 2008. The correct method to determine the average growth rate is through geometric averaging, resulting in an average annual growth rate of approximately 34.16%. This is derived from the formula for geometric mean, where the product of the growth factors (1.2 and 1.5) is used to calculate the average growth rate. The arithmetic average of the percentage increases is not applicable in this context.

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Dollydaggerxo
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I am just having trouble with percentages.

Lets say a town has a population of

1,000,000 in 2006
1,200,000 in 2007
1,800,000 in 2008

The percentage increase from
2006-2007 is 20%
2007-2008 is 50%

So, what I want to work out is the AVERAGE percentage per year.

The increase from 2006 to 2008 is 80%. So would it be 80%/2=40% per year?

OR

Would it be (20%+50%)/2 =35%

Neither of these actually give the right answer if you do 1,000,000*1.4^2, so was just wondering if this was even possible?
 
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Since you know the the average squared must equal the growth over the two years, taking he square root of the growth will give you the average. Now you just need to observe that the two year growth is the product of the two yearly growths: 1.2 \cdot 1.5 = 1.8, so avg = \sqrt {1.2 \cdot 1.5} = 1.34. So, 34% average growth.

This type of average is called geometric, as opposed to the more familiar arithmetic average.
 
Hi,

(1+x)^2=1,8
x=1,8^(0,5)-1=0,3416
34,16% of average augmentation each years
 

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