What is the average resultant force on a truck making a 90 degree turn?

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To determine the average resultant force on a truck making a 90-degree turn, the problem involves calculating the change in velocity and the resulting acceleration. The truck's mass is 3000 kg, with an initial speed of 4.0 m/s and a final speed of 7.0 m/s over a time interval of 5.0 seconds. The change in velocity (ΔV) must consider both the magnitude and direction, as it is a vector quantity. The average resultant force can be calculated using the formula F = m * a, where acceleration (a) is derived from ΔV/Δt. Understanding the vector nature of velocity is crucial for accurately solving this centripetal force problem.
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Homework Statement


a 3000 kg truck traveling at a speed of 4.0 m/s makes a 90 degree turn in a time of 5.0 s and emerges from this turn with a speed of 7.0 m/s. what is the magnitude of the average resultant force on the truck during this turn?


Homework Equations





The Attempt at a Solution


I think this might be a centripetal force problem but the change in velocities is messing me up.
 
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What is force? F = m*a

What is acceleration? ΔV/Δt

So ... what is the ΔV ... keeping in mind that V is a vector?

You have the Δt conveniently given as 5 sec.
 

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