Undergrad Axiom of Choice: Choosing Identical Objects

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SUMMARY

The Axiom of Choice (AC) is not required for finite sets of indistinguishable objects, such as identical socks, as one can simply select the first item. In the context of physics, real-world experiments involving finite quantities do not necessitate the Axiom of Choice, even in theoretical models like field theory. The discussion highlights that while the Axiom of Choice is essential for constructing bases in infinite-dimensional spaces, it does not impact practical measurements. The concept of transfinite induction, which relies on AC, raises questions about the existence of order in uncountable sets.

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  • Understanding of the Axiom of Choice in set theory
  • Familiarity with finite and infinite sets
  • Basic knowledge of mathematical induction and transfinite induction
  • Awareness of concepts in field theory and dimensional spaces
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TL;DR
Finite set of indistinguishables -- is axiom of choice required?
From Wikipedia entry on the Axiom of Choice:
Bertrand Russell coined an analogy: for any (even infinite) collection of pairs of shoes, one can pick out the left shoe from each pair to obtain an appropriate selection; this makes it possible to directly define a choice function. For an infinite collection of pairs of socks (assumed to have no distinguishing features), there is no obvious way to make a function that selects one sock from each pair, without invoking the axiom of choice.
[1] What about a finite set of indistinguishable things (e.g. identical socks)? Do we need to invoke the axiom?

[2] Is there any physical consequence of this axiom, i.e. is there any physics experiment where the calculations to predict the result must incorporate the axiom of choice, even indirectly? Perhaps some experiment involving identical particles, say?
 
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Swamp Thing said:
Summary:: Finite set of indistinguishables -- is axiom of choice required?

From Wikipedia entry on the Axiom of Choice:

[1] What about a finite set of indistinguishable things (e.g. identical socks)? Do we need to invoke the axiom?
No. We do not need AC in any case you can give an algorithm to make a choice. And if there are only finitely many things, just pick the first, e.g.
[2] Is there any physical consequence of this axiom, i.e. is there any physics experiment where the calculations to predict the result must incorporate the axiom of choice, even indirectly? Perhaps some experiment involving identical particles, say?
No. In the real world there are always only finitely many things involved in any experiment, even if you would count the particles. The infinities in models in field theory do not require AC either. It could only be important if we needed to construct a basis in an infinite dimensional space. I doubt that this is necessary and even if, then it probably hasn't any effects on real world measurements.
 
fresh_42 said:
And if there are only finitely many things, just pick the first, e.g.
If the notion of "first" exists for a finite number of pairs of things, then it's not clear why it becomes invalid for an infinite number of such pairs. If the Nth pair supports the notion of "first" and "second", then the (N+1)th pair should support it as well. Ad infinitum?
 
Swamp Thing said:
If the notion of "first" exists for a finite number of pairs of things, then it's not clear why it becomes invalid for an infinite number of such pairs. If the Nth pair supports the notion of "first" and "second", then the (N+1)th pair should support it as well. Ad infinitum?
Yes, but what about uncountably many? What is the first complex number? The examples always involve a description of a set, so we can probably choose one. But what if we can only prove existence? How to select such a solution?
 
Ok, I think I see. The very notion of Nth and N+1th may not exist for an uncountable set of collections. Is that it?
 
Swamp Thing said:
Ok, I think I see. The very notion of Nth and N+1th may not exist for an uncountable set of collections. Is that it?
Yes, one part of it. E.g. consider the interval ##[0,1)##. What is the last number in some ordering? Does it exist? AC has several equivalent formulations, one of it is that it does exist.
 
So in a sense, the axiom of choice implies that you can apply the principle of mathematical induction (arguing from Nth to N+1th) without being able to actually specify an N-like label for each collection?
 
Swamp Thing said:
So in a sense, the axiom of choice implies that you can apply the principle of mathematical induction (arguing from Nth to N+1th) without being able to actually specify an N-like label for each collection?
This is another concept, called transfinite induction. And yes, it requires the axiom of choice.
 
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