Morbert
Gold Member
- 929
- 728
- TL;DR Summary
- A sketch of the unistochastic reformulation of quantum mechanics applied to a basic entanglement swapping scenario, with a focus on causal relations implied by the principle of causal locality.
Consider four particles ##Q,R,S,T## (##Q,R## are entangled, as are ##S, T##) and three observer systems ##A,B,C##. At time ##t'##, ##A## makes a spin measurement of her choice on ##Q##, and ##B## makes a spin measurement of her choice on ##T##. Then, at time ##t''##, ##C## makes Bell-state measurement (BSM) or separable-state measurement (SSM) on ##R,S##.
I.e. In a conventional entanglement swapping experiment, we have initially have a tetraparticle system ##\psi^-_{QR}\psi^-_{ST}##. We also have Alice and Bob making measurements on particles ##Q## and ##T## while Charles makes a BSM or SSM on ##R,S##.
Barandes discusses divisible events in section F here. ##t'## and ##t''## correspond to divisible events, and so the unistochastic process ##\Gamma(t)## is\begin{eqnarray*}
\Gamma(t) = \Gamma(t\leftarrow t'')\Gamma(t'' \leftarrow t')\Gamma(t')
\end{eqnarray*}where
\begin{eqnarray*}
\Gamma(t') &=& \Gamma_{QR}(t')\otimes\Gamma_{ST}(t')\otimes\Gamma_A(t')\otimes\Gamma_B(t')\otimes\Gamma_C(t')\\
\Gamma(t''\leftarrow t') &=& \Gamma_{AQ}(t''\leftarrow t')\otimes\Gamma_{BT}(t''\leftarrow t')\otimes\Gamma_{R}(t''\leftarrow t')\otimes\Gamma_{S}(t''\leftarrow t')\otimes\Gamma_C(t''\leftarrow t')\\
\Gamma(t\leftarrow t'') &=& \Gamma_{AQ}(t\leftarrow t'')\otimes\Gamma_{BT}(t\leftarrow t'')\otimes\Gamma_{CRS}(t\leftarrow t'')\\
\end{eqnarray*}After the measurements conclude, we have the final distribution ##p(t) = \Gamma(t)p(0)##. We can identify the Bell-inequality-violating correlations between ##A## and ##B## concurrent with ##C##'s relevant BSM outcomes by computing conditional probabilities of interest ##p((a_t, b_t), t | c_t, t)##.
Similarly, we can identify causal relations with Barandes's principle of causal locality.
We can see that ##A## is free of causal influences by ##B, C, S, T## if\begin{eqnarray*}
p(a_t, t | (q_0,r_0,s_0,t_0,a_0,b_0,c_0), 0) = p(a_t, t | (q_0,r_0,a_0), 0)
\end{eqnarray*}Similarly, ##A, C, Q, R## don't exert causal influences on ##B## if\begin{eqnarray*}
p(b_t, t | (q_0,r_0,s_0,t_0,a_0,b_0,c_0), 0) = p(b_t, t | (s_0,t_0,b_0), 0)
\end{eqnarray*}I suspect these relations do hold, though proving them would be quite involved. For the purposes of this thread I will merely remark that these relations are what reveal causal relations according to Barandes's understanding of causality.
I.e. In a conventional entanglement swapping experiment, we have initially have a tetraparticle system ##\psi^-_{QR}\psi^-_{ST}##. We also have Alice and Bob making measurements on particles ##Q## and ##T## while Charles makes a BSM or SSM on ##R,S##.
Barandes discusses divisible events in section F here. ##t'## and ##t''## correspond to divisible events, and so the unistochastic process ##\Gamma(t)## is\begin{eqnarray*}
\Gamma(t) = \Gamma(t\leftarrow t'')\Gamma(t'' \leftarrow t')\Gamma(t')
\end{eqnarray*}where
\begin{eqnarray*}
\Gamma(t') &=& \Gamma_{QR}(t')\otimes\Gamma_{ST}(t')\otimes\Gamma_A(t')\otimes\Gamma_B(t')\otimes\Gamma_C(t')\\
\Gamma(t''\leftarrow t') &=& \Gamma_{AQ}(t''\leftarrow t')\otimes\Gamma_{BT}(t''\leftarrow t')\otimes\Gamma_{R}(t''\leftarrow t')\otimes\Gamma_{S}(t''\leftarrow t')\otimes\Gamma_C(t''\leftarrow t')\\
\Gamma(t\leftarrow t'') &=& \Gamma_{AQ}(t\leftarrow t'')\otimes\Gamma_{BT}(t\leftarrow t'')\otimes\Gamma_{CRS}(t\leftarrow t'')\\
\end{eqnarray*}After the measurements conclude, we have the final distribution ##p(t) = \Gamma(t)p(0)##. We can identify the Bell-inequality-violating correlations between ##A## and ##B## concurrent with ##C##'s relevant BSM outcomes by computing conditional probabilities of interest ##p((a_t, b_t), t | c_t, t)##.
Similarly, we can identify causal relations with Barandes's principle of causal locality.
In particular, causal separation follows from relations like equation (54) here.Barandes said:A theory with microphysical directed conditional probabilities is causally local if any pair of localized systems Q and R that remain at spacelike separation for the duration of a given physical process do not exert causal influences on each other during that process, in the sense that the directed conditional probabilities for Q are independent of R, and vice versa.
We can see that ##A## is free of causal influences by ##B, C, S, T## if\begin{eqnarray*}
p(a_t, t | (q_0,r_0,s_0,t_0,a_0,b_0,c_0), 0) = p(a_t, t | (q_0,r_0,a_0), 0)
\end{eqnarray*}Similarly, ##A, C, Q, R## don't exert causal influences on ##B## if\begin{eqnarray*}
p(b_t, t | (q_0,r_0,s_0,t_0,a_0,b_0,c_0), 0) = p(b_t, t | (s_0,t_0,b_0), 0)
\end{eqnarray*}I suspect these relations do hold, though proving them would be quite involved. For the purposes of this thread I will merely remark that these relations are what reveal causal relations according to Barandes's understanding of causality.
Last edited: