Is the Series Ʃ (1 + 2^n) / 3^n Convergent and What is Its Sum?

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SUMMARY

The series Ʃ (1 + 2^n) / 3^n from n=1 to infinity is analyzed for convergence and sum calculation. The series can be split into two parts: Ʃ (1/3^n) and Ʃ (2/3)^n. The second part converges since 2/3 < 1, while the first part is a geometric series with a common ratio of 1/3. The correct sum of the series is determined to be 3/2, despite initial miscalculations yielding 5/2.

PREREQUISITES
  • Understanding of geometric series and convergence criteria
  • Familiarity with the formula for the sum of a geometric series: S = a / (1 - r)
  • Basic knowledge of limits and infinite series
  • Ability to manipulate series notation and expressions
NEXT STEPS
  • Study the properties of geometric series in detail
  • Learn about convergence tests for infinite series
  • Explore advanced series manipulation techniques
  • Investigate the implications of series convergence in calculus
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Students studying calculus, particularly those focusing on series and sequences, as well as educators looking to clarify concepts related to convergence and series summation.

Saterial
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Homework Statement


Determine whether the series is convergent or divergent. Find the sum if possible

Ʃ 1+2^n / 3^n n=1 -> infinity


Homework Equations


a/1-r


The Attempt at a Solution



I split it up so that the equation is now:

Ʃ (1/3^n) + (2/3)^n n=1 -> infinity
Ʃ (1/3^n) + Ʃ (2/3)^n n=1 -> infinity

I know that it is convergent in the second term because 2/3 < 1, how do I setup a/1-r for term 1? :S

a1=1/3 a1 = 2/3
(1/3)/(1-(1/3)) + (2/3)/(1-(2/3))
=5/2

The answer should be 3/2 on the answer sheet it says ?
 
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Saterial said:

Homework Statement


Determine whether the series is convergent or divergent. Find the sum if possible

Ʃ 1+2^n / 3^n n=1 -> infinity


Homework Equations


a/1-r


The Attempt at a Solution



I split it up so that the equation is now:

Ʃ (1/3^n) + (2/3)^n n=1 -> infinity
Ʃ (1/3^n) + Ʃ (2/3)^n n=1 -> infinity

I know that it is convergent in the second term because 2/3 < 1, how do I setup a/1-r for term 1? :S

a1=1/3 a1 = 2/3
(1/3)/(1-(1/3)) + (2/3)/(1-(2/3))
=5/2

The answer should be 3/2 on the answer sheet it says ?

USE PARENTHESES!

I don't see anything wrong with your answer, but I had a hard time trying to figure out what your problem was.

This is what you wrote (fixed up in LaTeX):
$$ \sum_{n = 1}^{\infty} \left( 1 + \frac{2^n}{3^n}\right)$$

This is what I'm pretty sure you meant:
$$ \sum_{n = 1}^{\infty} \left(\frac{1 + 2^n}{3^n}\right)$$

Don't write 1+2^n / 3^n if you mean (1+2^n )/ 3^n.
 
The first sum, once you've broken them up, is not a geometric sum. Think about what that guy's doing for a little bit.
 
gustav1139 said:
The first sum, once you've broken them up, is not a geometric sum. Think about what that guy's doing for a little bit.
Sure it is.
The first series can be written as
$$\sum_{n = 1}^{\infty}\left(\frac{1}{3}\right)^n $$

or 1/3 + (1/3)2 + (1/3)3 + ... +
 
derp. right.
 
gustav1139 said:
The first sum, once you've broken them up, is not a geometric sum. Think about what that guy's doing for a little bit.

Had I been Mark44, I would have issued you a warning or infraction for that last sentence.
 
LCKurtz said:
Had I been Mark44, I would have issued you a warning or infraction for that last sentence.

I apologize. Personification is against the rules?
 
Last edited:
gustav1139 said:
The first sum, once you've broken them up, is not a geometric sum. Think about what that guy's doing for a little bit.

LCKurtz said:
Had I been Mark44, I would have issued you a warning or infraction for that last sentence.

gustav1139 said:
I apologize. Personification is against the rules?

I'm not the boss around here but I just wanted to alert you that your comment might easily be construed as violating the section below. It struck me that way anyway.

From the Rules menu at the top of the page:

language and Attitude: Foul or hostile language will not be tolerated on Physics Forums. This includes profanity, obscenity, or obvious indecent language; direct personal attacks or insults; snide remarks or phrases that appear to be an attempt to "put down" another member; and other indirect attacks on a member's character or motives.
 
Ah. When I said "that guy," I was referring to the first sum in the OP's question. I guess I see how that could be misconstrued.
 

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