solakis1 Messages 407 Reaction score 0 Thread starter Dec 9, 2020 #1 Prove: $A\leq B\wedge B\leq A\Rightarrow A=B$
HOI Messages 921 Reaction score 2 Dec 9, 2020 #2 Trichotomy: Given numbers A and B, one and only one must be true: 1) A> B 2) A< B 3) A= B Since [math]A\le B[/math], A> B is not true. Since [math]B\le A[/math], A< B is not true.
Trichotomy: Given numbers A and B, one and only one must be true: 1) A> B 2) A< B 3) A= B Since [math]A\le B[/math], A> B is not true. Since [math]B\le A[/math], A< B is not true.
solakis1 Messages 407 Reaction score 0 Dec 9, 2020 #3 Is the trichotomy law you are using Equivelant to the following: $A<B\vee B<A\vee A=B$