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Master1022
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- Quick question about calculation of immediate odds in a poker hand.
Hi,
Just have a quick conceptual question about calculating immediate odds in poker.
Question: Your hand is Ad Kd. The four cards on the table (flop and turn) are: Kd 7h 4d. What is the probability of getting a flop on the river? (scenario is that we are playing with one opponent)
At first, I thought that this would be calculated by doing [itex] P(diamond\, in\, the\, river) = \frac{\# \, diamonds\, left}{\# \, cards\, left} = \frac{9}{44} [/itex]. I have gotten the 9 from the fact that there are currently 4 known diamonds on the table (13 - 4 = 9) and there are 8 cards in play (52 - 8 = 44). However, the blog post quotes a different probability and when I work it back, they seem to use 46 in the denominator. I don't properly have an intuition of why we are including our opponents' cards in the total number of cards?
The answer quoted is: 19.56%
Thanks in advance.
Just have a quick conceptual question about calculating immediate odds in poker.
Question: Your hand is Ad Kd. The four cards on the table (flop and turn) are: Kd 7h 4d. What is the probability of getting a flop on the river? (scenario is that we are playing with one opponent)
At first, I thought that this would be calculated by doing [itex] P(diamond\, in\, the\, river) = \frac{\# \, diamonds\, left}{\# \, cards\, left} = \frac{9}{44} [/itex]. I have gotten the 9 from the fact that there are currently 4 known diamonds on the table (13 - 4 = 9) and there are 8 cards in play (52 - 8 = 44). However, the blog post quotes a different probability and when I work it back, they seem to use 46 in the denominator. I don't properly have an intuition of why we are including our opponents' cards in the total number of cards?
The answer quoted is: 19.56%
Thanks in advance.