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I've been given this problem involving allelic frequencies and I used the Hardy Weinberg's Law as an attempt to solve it

**Homework Statement**

In a sample of 35 people, 19 have specific smell hypersensitvity to asparagus. Calculate the frequency of the allele in this sample given that the trait is autosomal dominant.

**The attempt at a solution**

Here is my working...

I represented the autosomal dominant faulty gene by 'A' and the working copy of the gene by 'a'.

AA = ?

Aa = ?

aa = 16 <<< # genotype (aa): 35-19 = 16

Total 35

I knew that the frequency of non affected recessive individuals = 1/35

Hence q^2 = 1/35... thus q=0.169 (3dp)

Hence p = 1 - 0.169 = 0.831 (3dp)...it then follows p^2 = 0.691 (3dp)

So putting it all together i got... 2pq = 2 * 0.831 * 0.169 = 0.28059

So after that I thought we should multiply these frequencies by the 19 people before to calculate the individual genotype frequencies...

AA = 13 <<< (p^2*19)

Aa = 5 <<< (2pq*19)

aa = 16

Total = 34

But here my total adds up to only 34 people!!

I'm not sure if i'm doing it right or i'm missing something...

Please help, any suggestions will be greatly appreciated!!

v_phoenix