Starting with 75 light-colored beans and 25 dark-colored beans, the 100 beans represent my gene pool. Light beans = F and dark beans = f.
p = (total F alleles) / (total number of beans used)
And now I'm stuck where it's asking me to "practice determining the initial allele frequencies (p and q) for both F and F alleles, but change the top number to genotype ff x 2."
Hardy-Weinberg equation = p^2 + 2pq + q^2 = 1
The Attempt at a Solution
I got this far:
I have 75 light beans and 25 dark beans. Light beans = F and dark beans = f.
Number of offspring with genotype FF (2 light beans) = 75 x 2 = 150
Number of offspring with genotype Ff (one dark one light) = 25 x 1 = 25
Total F alleles = 175
I thought to find the allele frequencies of p and q in the next generation I had to square them and then do 2pq and add it, but nothing I do adds up to 1.