Book seems to say that we can have weak acid and weak conjugate base

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SUMMARY

The discussion centers on the equilibrium of weak acids and their conjugate bases, specifically the relationship between their strengths. It clarifies that both weak acids (HA) and their conjugate bases (A-) can exist at similar concentrations in a buffer solution, leading to the conclusion that both can be considered weak. The equilibrium constant, Ka, is defined as the ratio of the concentrations of hydronium ions and conjugate base to the weak acid, indicating that the pH of the solution is directly related to the strength of the acid. The discussion emphasizes that strength is relative, and both weak acids and bases can coexist in a buffer system with similar initial concentrations.

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Homework Statement
In the book I am reading there is a snippet that seems to indicate
Relevant Equations
that it is possible to have a weak acid with a weak conjugate base.

Here is the relevant section from the book
Consider the equilibrium

$$\mathrm{HA(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+A^-(aq)}\ \ \ \ \ K_a=\mathrm{\frac{[H_3O^+][A^-]}{[HA]}}$$

The values of ##\mathrm{[HA]}## and ##\mathrm{[A^-]}## that appear in ##K_a## are the equilibrium concentrations of acid and base in the solution, not the concentrations added initially.

However, a weak acid ##\mathrm{HA}## typically loses only a tiny fraction of its protons, and so ##\mathrm{HA}## is negligibly different from the concentration of the acid used to prepare the buffer, ##\mathrm{[HA]_{initial}}##.
This is all fine, but then there is the following
Likewise, only a tiny fraction of the weakly basic anions ##\mathrm{A^-}## accept protons, so ##\mathrm{[A^-]}## is negligibly different from the concentration of the base used to prepare the buffer, ##\mathrm{[A^-]_{initial}}##.
I am under the impression that if an acid is weak (ie, only a small fraction of the molecules donate protons) then the conjugate base is strong (a large fraction of the molecules accept protons).

But the snippet above seems to say that that both the acid and the conjugate base are weak.

How can this be?
 
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For a little more context, the topic is what happens when we create a buffer with the same initial concentrations of weak acid and conjugate base.

In the equilibrium in the OP, we would have ##\mathrm{[HA]=[A^-]}## and so

$$\mathrm{K_a=[H_3O^+]}$$

$$\implies \mathrm{pH=-\log{(K_a)}=pK_a}$$
 
Last edited:
Strong and weak are relative terms, not absolute. It is true that "the stronger the acid, the weaker the conjugate base", but we can't say "if one is (absolutely) strong, the other is (absolutely) weak". We can distinguish different situations:
A very strong acid (stronger than H3O+) has a very weak conjugate base (essentially non-basic in water).
A very strong base (stronger than OH-) has a very weak conjugate acid (essentially non-acidic in water).
In between these extremes we have an intermediate situation, where an acid weaker than H3O+ has a conjugate base weaker than OH-. Then in a solution of HA, only a small fraction of the HA molecules are deprotonated, while in a solution of A-, only a small fraction of the A- ions are protonated.
The acidity and basicity are linearly related on a logarithmic scale (pKa + pKb = 14), which means that in the mid-range, both Ka and Kb are small.
 
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