Breeding Ratio of thorium fuel cycle

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SUMMARY

The breeding ratio of a thorium fuel cycle in a breeder reactor generating 2.5 GW thermal power can be calculated using the production rate of U-233, which is 52 kg per year, and the capture to fission ratio of 0.09. The energy released per fission of U-233 is 197.9 MeV, equating to 81.95 TJ/kg. The breeding ratio formula is defined as the number of fissile nuclei produced divided by the number consumed, which requires understanding the relationship between energy production and fuel consumption in the reactor.

PREREQUISITES
  • Understanding of breeder reactor principles
  • Knowledge of thorium fuel cycle dynamics
  • Familiarity with nuclear fission and energy calculations
  • Basic grasp of breeding ratio calculations
NEXT STEPS
  • Calculate the breeding ratio using the provided production and consumption data
  • Research the implications of capture to fission ratios in nuclear reactors
  • Explore the energy conversion efficiency in breeder reactors
  • Study the thorium fuel cycle compared to traditional uranium cycles
USEFUL FOR

Nuclear engineers, physics students, and professionals involved in reactor design and fuel cycle analysis will benefit from this discussion.

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Homework Statement


A breeder reactor is designed to work on a thorium fuel cycle. If the reactor generates a constant thermal power of 2.5GW and a production rate of 233U is 52kg per year. Find the breeding Ratio

[You may assume the capture to fission ratio of 233U is 0.09 and the energy released per fission is 197.9Mev.]

Homework Equations


Breeding Ratio= number of fissile nuclei produced/ number of fissile nuclei consumed

The Attempt at a Solution


I really don't know how to go about solving this problem.
I would assume that the capture to fission ratio is important.

The fission of one atom of U-233 generates 197.9 MeV = 3.171 × 10−11 J, i.e. 19.09 TJ/mol = 81.95 TJ/kg.
Then multiply by 0.91 and calculate the energy from fission of 52kg.

81.95 TJ/kg x 52kg x 0.91=3.88x1015J per year

Also reactor produces 2.5GW so I can see this is also really important but get the feeling I am missing something simple as this is the 1st question on a past paper.

Any help really appreciated

Thanks
Lewis
 
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ha... I am stuck too lewis i swear this wasn't in his notes...

rate of production of new fuel = G w P = 52kg

G = C - 1

where C is the breeding ratio...

strugling to find w (think its to do with the 200 MeV) but i think its simpler than ur calculations
 
Last edited:

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