1. The problem statement, all variables and given/known data As shown in the figure below, a wooden cube measuring 20.0 cm on each side floats in water with 90.0% of its volume submerged. Suspended by a string below the wooden cube is a metal cube. The metal cube measures 10.0 cm on each side and has a specific gravity of 6.00. a) Taking the density of water to be 1000 kg/m^3, what is the density of the wooden cube? b) What is the tension in the string between the cubes? Assume the string itself has negligible mass and volume. Use g = 9.8 m/s^2. c) The pair of blocks is now placed in a different liquid. When the blocks are at equilibrium in this new liquid, the buoyant force acting on the wooden cube is exactly the same as the buoyant force acting on the metal cube. What is the density of this new liquid? 2. Relevant equations 1) Fb=p x V x g 2) P(object)/P(water)=V(displaced)/V(object) 3)? 3. The attempt at a solution I've only been trying to do part A (I've spent 1.5 hours on it already) by using equation 2, but I've only gotten this: (8.00m^3 x 90%)p(obj)= (1000kg/m^3)(8.00m^3), which means p(obj)=1111.1, but that doesn't take into account the second block, so I tried adding the [p(metal obj) x V (disp)] to the right side of the equation, but then I get 1944, which is wrong as well.