Calculate Arrow Speed & Height | Spring Energy Problem Homework

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The discussion revolves around calculating the speed and height of an arrow shot from a bow, given a mass of 0.30 kg and an average force of 192 N exerted over a distance of 1.3 m. The initial calculations provided by a user yield a speed of 28.85 m/s and a height of 42.4 m, but they are flagged as incorrect by Webassign. Other participants suggest that the energy should be calculated using the work done by the average force, leading to a reevaluation of the velocity. It is noted that the average force should be applied correctly in the energy equations, and a recalculation suggests a speed of 40.8 m/s instead. The conversation emphasizes the importance of correctly applying physics principles to solve the problem accurately.
whoopie88
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Homework Statement


An archer puts a 0.30 kg arrow to the bowstring. An average force of 192 N is exerted to draw the string back 1.3 m. Assume that air resistance is negligible.
(a) Assuming that all the energy goes into the arrow, with what speed does the arrow leave the bow?

(b) If the arrow is shot straight up, how high does it rise?

Homework Equations


All Energy/Work equations


The Attempt at a Solution


2hxo8pe.jpg


Thanks in advance for help!
 
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Those values look correct to me.
 
Really? o.o I'm doing a Webassign, and it's telling me that my values are incorrect.
I put in 28.85 m/s for (a) and 42.4 m for (b).

Is there something I'm missing? o.o
 
whoopie88 said:
Really? o.o I'm doing a Webassign, and it's telling me that my values are incorrect.
I put in 28.85 m/s for (a) and 42.4 m for (b).

Is there something I'm missing? o.o

Given the values, it should be correct. Realistically speaking, 1.3 m is quite large for an archer to stretch the string.
 
whoopie88 said:
Really? o.o I'm doing a Webassign, and it's telling me that my values are incorrect.
I put in 28.85 m/s for (a) and 42.4 m for (b).

Is there something I'm missing? o.o

The "average" force is F, so the energy is F * 1.3

or

F = 192 = K* X /2 not K * X

So the velocity is 28.85 * sqrt(2) = 40.8m/sec
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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