Calculate Arrow Speed & Height | Spring Energy Problem Homework

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SUMMARY

The discussion centers on calculating the speed and height of an arrow shot from a bow, given specific parameters: a 0.30 kg arrow, an average force of 192 N, and a draw distance of 1.3 m. The initial calculations provided by a user yielded a speed of 28.85 m/s and a height of 42.4 m, which were deemed incorrect. The correct approach involves using the work-energy principle, where the energy exerted on the arrow is calculated as the product of force and distance, leading to a revised speed of approximately 40.8 m/s when factoring in the correct energy equations.

PREREQUISITES
  • Understanding of the work-energy principle in physics
  • Familiarity with basic kinematics equations
  • Knowledge of force, mass, and acceleration relationships
  • Ability to perform calculations involving energy and motion
NEXT STEPS
  • Review the work-energy theorem and its applications in projectile motion
  • Learn about kinematic equations for vertical motion in physics
  • Explore the concept of potential energy and its relation to height
  • Investigate the effects of air resistance on projectile motion
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the mechanics of projectile motion and energy transfer in archery contexts.

whoopie88
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Homework Statement


An archer puts a 0.30 kg arrow to the bowstring. An average force of 192 N is exerted to draw the string back 1.3 m. Assume that air resistance is negligible.
(a) Assuming that all the energy goes into the arrow, with what speed does the arrow leave the bow?

(b) If the arrow is shot straight up, how high does it rise?

Homework Equations


All Energy/Work equations


The Attempt at a Solution


2hxo8pe.jpg


Thanks in advance for help!
 
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Those values look correct to me.
 
Really? o.o I'm doing a Webassign, and it's telling me that my values are incorrect.
I put in 28.85 m/s for (a) and 42.4 m for (b).

Is there something I'm missing? o.o
 
whoopie88 said:
Really? o.o I'm doing a Webassign, and it's telling me that my values are incorrect.
I put in 28.85 m/s for (a) and 42.4 m for (b).

Is there something I'm missing? o.o

Given the values, it should be correct. Realistically speaking, 1.3 m is quite large for an archer to stretch the string.
 
whoopie88 said:
Really? o.o I'm doing a Webassign, and it's telling me that my values are incorrect.
I put in 28.85 m/s for (a) and 42.4 m for (b).

Is there something I'm missing? o.o

The "average" force is F, so the energy is F * 1.3

or

F = 192 = K* X /2 not K * X

So the velocity is 28.85 * sqrt(2) = 40.8m/sec
 

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