Calculate ΔH°rxn for 3NO2(g)+1H2O(l) → 2HNO3(g)+1NO(g)

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Homework Statement



Using the enthalpies of formation given below, calculate ΔH°rxn in kJ, for the following reaction.

3NO2(g)+1H2O(l) -> 2HNO3(g)+1NO(g)

NO2 (g): 33.10 kJ/mol
H2O (l): -285.83 kJ/mol
HNO3 (l): -174.10 kJ/mol
NO (g): 90.29 kJ/mol

Homework Equations



dHrxn = dHproducts - dHreactants

The Attempt at a Solution



Is this possible to do since the equation says HNO3 is a gas, but they give the enthalpy of formation for HNO3 as a liquid.
 
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its possible but you need to use another enthalpy term that accounts for the latent heat which is from the phase transfer of liquid to gas