Calculate Distance of 5Kg Object on Frictional Surface: Matt's Help

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SUMMARY

The discussion centers on calculating the distance traveled by a 5 kg object on a frictional surface when a force of 15 N accelerates it to a velocity of 12 m/s. The user, Matt, initially attempts to rearrange the equation A = (V - U) / t to find time, but struggles with the calculations. The correct approach involves using the kinematic equation V² = 2*a*x, where acceleration (a) is determined to be 3 m/s². This leads to the conclusion that the distance can be accurately calculated using the established kinematic formulas.

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  • Understanding of Newton's Second Law of Motion
  • Familiarity with kinematic equations
  • Basic knowledge of acceleration, velocity, and distance relationships
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  • Study the kinematic equations in detail, focusing on V² = 2*a*x
  • Learn how to derive acceleration from force and mass using F = m*a
  • Explore the concept of friction and its impact on motion
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Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in understanding the principles of motion and kinematics.

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the problem is i have an object which has a mass of 5Kg it is on a frictional Surface a force of 15n acts on it which accelerates it to 12ms-1 i don't even know where to start to work out the distance i was thinking could you rearrange A= V-U divided by t (sorry it won't let me do the proper equation)


Into T= (V+U) x A
to work to work out time so i can put it into the Distance, Speed Time Triangle.
but
the answer 144 doesn't seem right am i doing it right or just going totality wrong ?

Thanks for your help in advance Matt
 
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Physics258744 said:
the problem is i have an object which has a mass of 5Kg it is on a frictional Surface a force of 15n acts on it which accelerates it to 12ms-1 i don't even know where to start to work out the distance i was thinking could you rearrange A= V-U divided by t (sorry it won't let me do the proper equation)


Into T= (V+U) x A
to work to work out time so i can put it into the Distance, Speed Time Triangle.
but
the answer 144 doesn't seem right am i doing it right or just going totality wrong ?

Thanks for your help in advance Matt

Welcome to PF.

Here are some equations that may address your interest in kinematics.

https://www.physicsforums.com/showpost.php?p=905663&postcount=2

From your force equation you know acceleration is 3m/s
Your final velocity is 12?

V2 = 2*a*x
 
Thank you :)
 

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