Calculate enthalpy change from KOH and HBr neutralization

[Frank665]

Use the experimental values to calculate the enthalpy change in the system.

Observation Experiment
Quantity of reactant 1 100.0 mL of 1.00 M KOH(aq)
Quantity of reactant 2 100.0 mL of 1.00 M HBr(aq)
Initial Temperature (oC) 20.0
Final Temperature (oC) 22.5

 

[lightarrow]

Use the experimental values to calculate the enthalpy change in the system.

Observation Experiment
Quantity of reactant 1 100.0 mL of 1.00 M KOH(aq)
Quantity of reactant 2 100.0 mL of 1.00 M HBr(aq)
Initial Temperature (oC) 20.0
Final Temperature (oC) 22.5

If your teacher didn't give you the (constant pressure, I assume) specific heats, it should mean he assumes you use the one of water, so you can easily find the heat exchanged (at constant pressure it's = enthalpy variation).
Of course I won't make the computations for you, this is an homework.