Calculate Enthalpy Change of N2 + O2 Reaction

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SUMMARY

The enthalpy change for the reaction between nitrogen gas (N2) and oxygen gas (O2) to form dinitrogen pentoxide (N2O5) can be calculated using Hess's law and the provided thermochemical equations. The relevant equations are: (1) 2H2(g) + O2(g) → 2H2O(l) with H = -572 kJ, (2) N2O5(g) + H2O(l) → 2HNO3(l) with H = -77 kJ, and (3) 1/2 N2(g) + 3/2 O2(g) + 1/2 H2(g) → HNO3(l) with H = -174 kJ. By rearranging these equations, the enthalpy change of formation for N2O5 can be determined, confirming that N2O5 is the product of the reaction.

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jalen
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Calculate the enthalpy change of the following reaction between nitrogen gas and oxygen gas, given thermochemical equations (1),(2),and(3).
(1) 2H2(g) + O2(g) ---> 2H2O(l) H=-572KJ
(2) N2O5 (g) + H2O(l) --->2HNO3 (l) H=-77KJ
(3)1/2 N2 (g) + 3/2 O2 (g) +1/2 H2 (g) ---> HNO3 (l) H=-174KJ
 
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write equation of the reaction of nitrogen with oxygen. what is the product?

notice that nitrogen and oxygen are both elements in their standard conditions. the product will be N2O5 only, so the equation is the enthalpy change of formation of N2O5.

you only have to rearrange the above 3 eqns to obtain the enthalpy of formation of N2O5.
 

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