Calculate Euler Buckling Load with Different End Fixity Conditions

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Discussion Overview

The discussion revolves around calculating the Euler buckling load for a steel rod with different end fixity conditions. Participants explore the implications of various boundary conditions on the buckling load, including pinned-pinned, fixed-fixed, and fixed-free configurations.

Discussion Character

  • Technical explanation, Homework-related, Mathematical reasoning

Main Points Raised

  • One participant calculates the Euler buckling load for a steel rod pinned at both ends, arriving at a value of 259.1 kN using a specific formula.
  • The same participant identifies three other end fixity conditions: pinned-fixed, fixed-fixed, and fixed-free, providing the corresponding equations for each case.
  • Another participant seeks clarification on the type of help needed, noting that the equations have been identified.
  • A further participant suggests that calculations must be performed for the equations provided.
  • Another comment implies a straightforward approach to solving the problem, referred to as "plug and chug."

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the need for calculations or the specific type of assistance required, indicating some uncertainty regarding the next steps in the discussion.

Contextual Notes

The discussion lacks detailed assumptions regarding material properties or specific values for the modulus of elasticity and moment of inertia, which are critical for the calculations. Additionally, the mathematical steps for the calculations remain unresolved.

Who May Find This Useful

Students or professionals interested in structural engineering, mechanics of materials, or those studying buckling phenomena may find this discussion relevant.

thebest99
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a steel rod, 40mm in diameter and 1.00m long is pinned at each end

calculate the euler bucking load

Answer:

using PE = pie sqaured 210x10cubed kN/mm x 1.25 x 10power 5mm to the 4 divided by 1000mm sqaured

=259.1kN

b) indentify three other possible end fixity conditions for the rod and demonstrate how the Euler buckling load will be effected in each case

i have pinned -fixed, PE=2.04pie sqaured EI divided by L sqaured

fixed -fixed , PE= 4pie sqaured EI dived by L sqaured
and fixed free, PE= quater pie sqaured EI divide by L sqaured

can someone help with question b.

thnak you
 
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What sort of help are you looking for? You've identified 3 other end conditions and noted how it affects the critical buckling load.
 
believe i have to do the calculations too for the equations
 

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