Calculate Kp for CO + 2H2 to CH3OH(g) Equilibrium

In summary, Kp is the equilibrium constant for gases and is used to quantify the extent of a reversible reaction at a given temperature. To calculate Kp, the balanced chemical equation must be written and the molar ratios of the reactants and products must be determined. Kp is specific to a particular temperature and indicates the direction of the reaction. Changing the pressure or volume of a system at equilibrium does not affect the value of Kp.
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zorro
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Homework Statement


0.15 mole of CO is taken in a 2.5L flask is maintained at 705K along with a catalyst so that the folwing reaction takes place

CO + 2H2 ---> CH3OH(g)

Hydrogen is introduced till the total pressure of the system is 8.5atm at equilibrium and 0.08 mole of methanol is formed. Calculate Kp.


Homework Equations





The Attempt at a Solution



Here do we have to take any initial concentration of H2?
Or do we have to assume that there is no H2 present initially (only 0.15 mole CO)
 
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  • #2
No H2 at first, only CO.
 

FAQ: Calculate Kp for CO + 2H2 to CH3OH(g) Equilibrium

1. What is Kp and how is it related to equilibrium?

Kp is the equilibrium constant for gases and is used to quantify the extent of a reversible reaction at a given temperature. It is calculated using the partial pressures of the reactants and products at equilibrium.

2. How do you calculate Kp for the reaction CO + 2H2 to CH3OH(g)?

To calculate Kp for this reaction, you first need to write the balanced chemical equation and determine the molar ratios of the reactants and products. Then, using the ideal gas law, you can calculate the partial pressures of each species at equilibrium. Finally, plug these values into the Kp expression: Kp = (pCH3OH / pCO) * (pCH3OH / pH2)^2.

3. Can Kp be calculated at any temperature?

No, Kp is specific to a particular temperature. As temperature changes, so does the value of Kp. Therefore, it is important to specify the temperature at which Kp is being calculated.

4. How does the value of Kp indicate the direction of the reaction?

If Kp is greater than 1, the reaction is product-favored, meaning the products are present at a higher concentration at equilibrium. If Kp is less than 1, the reaction is reactant-favored, meaning the reactants are present at a higher concentration at equilibrium. If Kp is equal to 1, the reaction is at equilibrium and the concentrations of reactants and products are equal.

5. How does changing the pressure or volume affect the value of Kp?

Changing the pressure or volume of a system at equilibrium does not affect the value of Kp. This is because Kp is a constant that is dependent on the temperature and the nature of the reaction, not the conditions of the system.

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