Chemistry Calculate Moles of NaOH: Homework Help

  • Thread starter Thread starter homevolend
  • Start date Start date
  • Tags Tags
    Moles
Click For Summary
SUMMARY

The discussion centers on calculating the moles of NaOH used in a titration reaction with acetic acid. The key issue is the lack of known molarity for the NaOH solution, which is essential for using the formula c = n / V to determine moles. Participants emphasize that without the concentration of either reactant, the calculation cannot be performed. Additionally, references to the number 22.4, which pertains to the volume of a mole of gas at STP, are clarified as irrelevant to this titration scenario.

PREREQUISITES
  • Understanding of titration principles and procedures
  • Knowledge of the formula c = n / V (concentration = moles/volume)
  • Familiarity with molarity and its significance in chemical reactions
  • Basic concepts of stoichiometry in acid-base reactions
NEXT STEPS
  • Research how to determine molarity from titration data
  • Learn about the role of indicators in titration and their effect on results
  • Study the concept of stoichiometric ratios in acid-base reactions
  • Explore the significance of standard temperature and pressure (STP) in gas calculations
USEFUL FOR

Chemistry students, laboratory technicians, and educators involved in teaching acid-base titration techniques and stoichiometry.

homevolend
Messages
47
Reaction score
0

Homework Statement



Calculate the moles of NaOH in the reaction of NaOH + acetic acid. This is a titration where the NaOH neutralized the acetic acid. It took 0.02 L of NaOH to neutralize 3 ml of acetic acid. I just do not know what to do, have been trying for a few days and can't seem to get it.


Homework Equations


Can't use the moles = M x L because I don't know the Molarity.

I am thinking that I have to use some other law but not sure what one...

I did the lab at room temp, not sure if that makes a differnce or not.

thanks, help greatly appreciated.


The Attempt at a Solution

 
Physics news on Phys.org
My friend, unless you know the concentration of the sodium hydroxide or the acetic acid that you used in the laboratory titration, there is no way you will be able to calculate the number of moles of NaOH used up in the process.

The room temperature cannot hint at the number of moles as the two quantities are apparently unrelated.

You were right to quote the formula c = n / V, where c is the concentration, n is the number of moles and V is the volume. However, you need the concentration of either of the acids to work out the number of moles of NaOH.

You didn't record the concentrations in your lab book, did you?
 
Well, we did not get the concentrations. We put the NaOH in a burette then recorded the initial and final volume. Also recorded the amount of acetic acid used.

I think some are calculating moles by using the number 22.4 not sure what that means though?
 
homevolend said:
Well, we did not get the concentrations.

Then whole procedure doesn't make sense. You need a concentration. It is usually either written on the bottle or told by TA or whoever takes care of the lab.

I think some are calculating moles by using the number 22.4 not sure what that means though?

It means nothing. 22.4L is a volume of 1 mole of gas at STP. There are also several other numbers they can use - like 3.14 (pi), or 2.78 (e). They don't make more sense though, they are just a way of showing creativity.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 23 ·
Replies
23
Views
3K
Replies
7
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K