SUMMARY
The pH of a 150 mL aqueous solution of 2.13 x 10^-3 M HCl is calculated using the formula pH = -Log(2.13 x 10^-3), resulting in a pH of 2.672. For the second query regarding a 0.1 M aqueous solution of acid HA with a pH of 4.0, the pKa can be determined by rearranging the formula for pH to find Ka, and subsequently calculating pKa. The discussion emphasizes the importance of significant figures in reporting results, suggesting a pKa of approximately 2.67 based on the provided pH.
PREREQUISITES
- Understanding of pH and pKa concepts
- Familiarity with logarithmic calculations
- Knowledge of acid dissociation constants (Ka)
- Basic chemistry principles related to aqueous solutions
NEXT STEPS
- Study the relationship between pH, pKa, and Ka in acid-base chemistry
- Learn how to rearrange the pH formula to solve for pKa
- Review significant figures in scientific calculations
- Explore online resources or lectures on pH calculation techniques
USEFUL FOR
Chemistry students, educators, and professionals involved in analytical chemistry or acid-base equilibria who seek to deepen their understanding of pH and pKa calculations.
