Calculate Rh value from Rydberg Equation

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Homework Statement


λ for one line of the hydrogen spectrum is .4118 x 10-4 cm. Use this value in the Rydberg equation to calculate the RH value using n1 = 2, and n2 = 3.


Homework Equations


## \frac{1}{ \lambda } = \frac{R_{h}}{hc} ( \frac{1}{n_{x}^{2}}-\frac{1}{n_{y}^{2}})##
## \frac{1}{ \lambda } = R( \frac{1}{n_{x}^{2}}-\frac{1}{n_{y}^{2}})##
##\lambda = 0.4118 x 10^{-4} cm= 4.118 x 10^{-5} cm = 4.118 x 10^{-7}m##
##x_{1} = 2##
##X_{2} = 3##
##h=6.626 x 10^{-34} J*s##
##c=2.998 x 10^{8} m/s##

The Attempt at a Solution


## \frac{1}{4.118 x 10^{-7}m} = \frac{R_{h}}{(6.626 x 10^{-34} J*s)(2.998 x 10^{8} m/s)} ( \frac{1}{2^{2}}-\frac{1}{3^{2}})##
##R_{h}=3.473x10^{-18}##
This is wrong however
 
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This is the right answer as far as I can tell. Maybe your answer got auto-rejected from a web-based homework form for the wrong number of sig figs?
 
TeethWhitener said:
This is the right answer as far as I can tell. Maybe your answer got auto-rejected from a web-based homework form for the wrong number of sig figs?
Or they might want an ## E ## in place of your ## x ##. ## R_H ## needs to be defined, and what units are they looking for=SI/MKS or electron-volts? The statement of the problem appears to be poorly defined. (A google showed this same question appeared on the Chem Forums website.)