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## Homework Statement

I've got a flywheel of Inertia = 0.0019302kg/m^2 (found via solidworks), when a torsion spring is released, a force of 10N acts on the wheel via astring attached 0.065m above and 0.0325m to the right of the wheel's axis at an angle of 40 degrees.

## Homework Equations

What is the flywheel's RPM (or rad/s or Hz)?

## The Attempt at a Solution

Torque produced = FhDv + FvDh = (10*sin(40))0.0325 + (10*cos(40))0.065

= 0.667Nm

Torque = Ia

a = Torque/I = 0.667/0.0019302

= 345.5 rad/s(?)

Am i lacking a length of time this torque is applied for? I struggle to se where to go from here[/B]