MHB Calculate Selling Price for Cucumbers inc. VAT (42% Profit Margin)

  • Thread starter Thread starter LizQUIZE
  • Start date Start date
LizQUIZE
Messages
1
Reaction score
0
The grocery stores goal profit margin is 42% from selling price apart from the wastage. What is the selling price for the cucumbers including VAT when the purchase price (without VAT) is 1,30$ and about 90 % are sold from the purchased cucumbers? The VAT for food is 14 % year 2016.I do not know where to start with this one.
 
Last edited:
Mathematics news on Phys.org
Suppose n cucumbers are bought for 1,30 the total cost is 1,30n. Let the selling price be p. If, because of wastage, on 90% of those cucumber, 0,9n, can be sold, you will bring in 0,9np. Your "value added" will be (0,9np- 1,30n)= (0,9p- 1,30)n so VAT will be 0,14(0,9- 1,30)n. You want to make a profit of 42% of the selling price so you want 0,9np- 0,14(0,9- 1,30)n- 1,30n= 0.42n. Divide through by n to get 0,9p- 0,14(0,9p- 1,3)= 0,42. Solve that equation for p.
(I had to drop all currency signs because they were interpreted as delimiters.)
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top