Calculate the inverse of f(x) = x^3 = 3x^2 + 3x -1

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SUMMARY

The discussion focuses on calculating the inverse of the function f(x) = x^3 - 3x^2 + 3x - 1. Participants suggest using polynomial long division after identifying a root x0 that satisfies f(x) = 0. The conversation highlights the use of Pascal's Triangle as a simpler method for factoring the polynomial, which can facilitate finding the inverse function more efficiently.

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mooneh
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f inverse for f(x)= x^3-3x^2+3x-1

i thought of taking x common factor x(x^2-3x+3)-1
but i got stuck with the quadratic equation !
HELP...
 
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The coefficients of x^3, x^2, x, and 1 are +1, -3, +3, -1, an interesting pattern. Can you guess a value of x that makes f(x)=0 ? Call that value x0. Then, you can divide f(x) by x-x0 using polynomial long division: http://www.purplemath.com/modules/polydiv2.htm. That will give you a quadratic that you can factorize.
 
better yet to factorise...from x^3-3x^2 is there any factor you can't take out to make it 3x-1?
 
Sorry!, please note that the rules for the Homework Help forums explicitly state that full answers should never be given to students.
 
ooooh my bad. sorry about that cristo... i never saw a post about rules :o

but yeah... mooneh have you ever used or heard of Pascals Triangle before it's much easier to factor than long/synthetic division etc. etc. especially for the particular function you stated... from there you just solve to get the inverse
 
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