Calculate the period of a ball bouncing between two walls

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Homework Statement
A particle of mass ##m## moves with velocity ##v_0## and collides with the wall. Determine the period of oscillation if:
A) The collisions are perfectly elastic
B) The kinetic energy of the ball decreases 2 % with every collision. The period will be a function of the number of collisions.
Relevant Equations
##d=tv##
For A) I just have to calculate the time taken to travel from the middle to the wall and multiply that number by 4, since it travels the same distance 4 times.
##t=\frac{x_0}{v_0}##

B)The energy is an exponential function
##T(n)=T_0.(1-\frac{2}{100})^n##
So
##v^2={v_0}^2.(1-\frac{2}{100})^n##

Then I just have to replace that value in the formula from the previous exercise (taking into account that the latest expression is squared)

Is this right?
 
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Like Tony Stark said:
Homework Statement:: A particle of mass ##m## moves with velocity ##v_0## and collides with the wall. Determine the period of oscillation if:
A) The collisions are perfectly elastic
B) The kinetic energy of the ball decreases 2 % with every collision. The period will be a function of the number of collisions.
Relevant Equations:: ##d=tv##

For A) I just have to calculate the time taken to travel from the middle to the wall and multiply that number by 4, since it travels the same distance 4 times.
##t=\frac{x_0}{v_0}##

B)The energy is an exponential function
##T(n)=T_0.(1-\frac{2}{100})^n##
So
##v^2={v_0}^2.(1-\frac{2}{100})^n##

Then I just have to replace that value in the formula from the previous exercise (taking into account that the latest expression is squared)

Is this right?
Yes, that's a good approximation, but strictly speaking one oscillation will involve (if it starts in the middle) three different speeds.
 
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