- #1

DryRun

Gold Member

- 838

- 4

- Homework Statement
- Calculate the phase angle between two sinusoids.

- Relevant Equations
- v1(t) = -10cos(wt + 50) and v2(t) = 12sin(wt-10)

I am trying to do exactly what was stated, by finding it with calculations only, so, without having to draw the curves. Is that possible?

Here is my attempt:

v1(t) = -10cos(wt + 50) and v2(t) = 12sin(wt-10)

v1(t) = -10cos(wt + 50) becomes v1(t) = -10sin(wt+50+90) = v1(t) = -10sin(wt+140)

Now, i have these equations: v1(t) = -10sin(wt+140) and v2(t) = 12sin(wt-10).

If there was no negative sign in front of the 10, then i could have simply found the phase angle by: 140--10 = 150 degrees, but since it has a negative sign, I'm not sure what to do.

Here is my attempt:

v1(t) = -10cos(wt + 50) and v2(t) = 12sin(wt-10)

v1(t) = -10cos(wt + 50) becomes v1(t) = -10sin(wt+50+90) = v1(t) = -10sin(wt+140)

Now, i have these equations: v1(t) = -10sin(wt+140) and v2(t) = 12sin(wt-10).

If there was no negative sign in front of the 10, then i could have simply found the phase angle by: 140--10 = 150 degrees, but since it has a negative sign, I'm not sure what to do.