Calculating acceleration when only have time and distance

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artworkmonkey
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Homework Statement


A car travels 400m in 60s. The first 10s it accelerates from stationary. The last 10 seconds it decelerates back to stationary. For the middle 40s it has a constant velocity. What is the acceleration?

Homework Equations


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The Attempt at a Solution


Using only time and distance traveled I can only think how to calculate the average velocity: Vave = distance traveled / time = 6.67 m/s. I don't so much need an answer, more some guidance of where to begin. I'm pretty stuck. Thanks
 
Maybe start graphically? You might find some inspiration. Make a sketch of velocity versus time. You don't know the cruising speed yet, so leave that as a variable. Now, what do you know about the area under a velocity vs time graph?
 
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The area under the graph should equal the displacement, so the total area should equal 400m. I have drawn a graph (attached). When a put the acceleration and deceleration together the area is exactly one 5th of the time spent cruising: therefore, the amount of time spent accelerating and decelerating is one 5th of 400m = 80 meters. Divide this by 2 and the car moved 40 meters in 10 seconds.
Acceleration = distance/time^2 = 40m/10^2 = 0.4m/s

Does this sound right? Making a sketch was good advise because it is starting to make sense to me. Just hope I have taken a wrong turn somewhere.
Thanks :)
 
Attachments
  • Two velocity against time graphs labelled a and b. Graph a is a trapezoid: velocity rises linearly from 0 at time 0 to 10 s, stays constant until 50 s, then falls linearly to 0 at 60 s. Graph b is a rectangle-like shape: velocity is constant from 10 s to 50 s, drops sharply to 0 at 60 s with a sloped line.
    Time vs Velocity.png
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Very close indeed. However: ##distance = \frac{1}{2} Acceleration \cdot time^2##. So fix that up and you should be good.
 
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Yay! Thank you for your help. I've been staring at this question since yesterday, and actually drawing it was brilliant advice. Thank you!